We may use Stokes' Theorem to deduce this by applying it to a tiny rectangle normal to the w
1 direction with sides obeying one of dw
2� = 0 and dw
3� = 0, and then cyclically permuting the indices.
The surface integral in Stokes' theorem then becomes
u
2u
3dw
2dw
3(
v)
1while the path integrals become
which gives us:
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